C Program to count number of digits in a number
Write a C Program to count the number of digits in a number using a loop and without using a loop. How to find the number of digits in a number using a loop and without using a loop. Logic to find the number of digits in a number using while and without using loop by log10.
C Program to count number of digits in a number using while loop
#include <stdio.h>
void main()
{
int num, count = 0;
printf("Enter number: ");
scanf("%d", &num);
while(num > 0)
{
num = num / 10;
count++;
}
printf("Number of digits: %d", count);
}
C Program to count the number of digits in a number without using loop - by log10
#include <stdio.h>
void main()
{
int num, count;
printf("Enter number: ");
scanf("%d", &num);
if (num == 0)
count = 1;
else
count = log10(num) + 1;
printf("Number of digits: %d", count);
}
Output
Enter number: 1234
Number of digits: 4